(6/5)^n=2

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Solution for (6/5)^n=2 equation: 



(6/5)^n=2

We move all terms to the left:

(6/5)^n-(2)=0



Domain of the equation: 5)^n!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

(+6/5)^n-2=0

We multiply all the terms by the denominator


(+6-2*5)^n=0

We add all the numbers together, and all the variables

(-4)^n=0

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